Case 1
- Bottom radius
- 5
- Top radius
- 3
- Vertical height
- 4
219.211186
Open with these valuesChange any value to update the result.
219.211186units²
Total surface area: 219.211186 units²Enter the vertical height, not the slanted side — this one works the slant out for you, as √((R − r)² + h²). The total covers both circular ends plus the curved band between them. For an open bucket, subtract the top circle πr².
Held fixed: Bottom radius 5.000, Top radius 3.000.
| Vertical height | Total surface area |
|---|---|
| 1.000 | 163.012668 |
| 2.000 | 177.900277 |
| 3.000 | 197.431537 |
| 4.000Your value | 219.211186 |
| 5.000 | 242.158104 |
| 6.000 | 265.767562 |
| 7.000 | 289.783268 |
| 8.000 | 314.064044 |
219.211186
Open with these values436.022409
Open with these values753.242398
Open with these valuesA = π(R + r)·√((R − r)² + h²) + πR² + πr²
| Bottom, top, height | Slant | Total area |
|---|---|---|
| 1, 0.5, 2 | 2.061553 | 13.641830 |
| 2, 1, 1 | 1.414214 | 29.036612 |
| 5, 3, 4 | 4.472136 | 219.211186 |
| 7, 4, 6 | 6.708204 | 436.022409 |
| 10, 2, 8 | 11.313708 | 753.242398 |
Add the two circular ends to the curved band: π(R + r) times the slant height, plus πR² and πr². A frustum with radii 5 and 3 and height 4 comes to about 219.21 square units.
The vertical height. The calculator derives the slant itself from √((R − r)² + h²), which is 4.472136 for radii 5 and 3 with height 4.
Subtract the top circle, πr². For radii 5 and 3 that is π × 9, about 28.27, leaving roughly 190.94 square units of material.
Because the side leans outward as well as rising. Only when both radii are equal do the two coincide, and the frustum becomes a cylinder.
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