- Half-life
- 5730
- Elapsed time
- 5730
50.000000%
Open with these values50.000000%
Result: 50.000000 %After one half-life 50 % remains, after two 25 %, after three 12.5 %. The share left depends only on how many half-lives have passed, never on how much you started with. Enter the half-life and the elapsed time in the same unit — years against years, hours against hours.
50.000000%
Open with these values25.000000%
Open with these values12.500000%
Open with these valuesshare = 100 × ½^(t ÷ t½)
| Half-life, elapsed time | Half-lives passed | Still present (%) |
|---|---|---|
| 5730, 0 | none | 100.000000 |
| 10, 5 | half of one | 70.710678 |
| 5730, 5730 | one | 50.000000 |
| 5730, 11460 | two | 25.000000 |
| 8, 24 | three | 12.500000 |
| 10, 33.2 | about 3.32 | 10.013373 |
A half-life is the time it takes for half of a quantity to decay or be removed. After one half-life 50 % remains, after two 25 %, after three 12.5 %. Because the decay is exponential the amount never reaches exactly zero — it just keeps halving.
Divide the elapsed time by the half-life to get the number of half-lives, then halve 100 % that many times. Written out that is 100 × ½^(t ÷ t½), and the exponent does not have to be a whole number.
Yes. Both must use the same time unit — both in years, both in hours, both in seconds. Only their ratio enters the formula, so the units cancel; mixing years with days gives a wrong answer.
Because it cannot change the percentage. One gram and one kilogram both leave 25 % after two half-lives. If you want the absolute amount left rather than the share, use the radioactive decay calculator instead.
It describes any exponential decay: radioactive isotopes and carbon-14 dating, the clearance of a drug from the bloodstream, the discharge of a capacitor. The same formula applies wherever a quantity falls by a fixed fraction over equal time intervals.
The exponent becomes zero, and anything raised to the power zero is one, so 100 % is still present. That is the sanity check at the top of the table.
Information, not professional advice.
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