- Inductance L (H)
- 2H
- Current I (A)
- 3A
9.000000J
Open with these values9.000000J
Result: 9.000000 JHalf the inductance times the current squared gives joules: a 2 H coil carrying 3 A holds 9 J. The current is squared, so its direction does not matter and doubling it quadruples the energy. Enter henries, not millihenries: a 5 mH choke is 0.005 H.
Held fixed: Inductance L (H) 2.000000000000 H.
| Current I (A) (A) | Result (J) |
|---|---|
| 0.000 | 0.000000 |
| 1.000 | 1.000000 |
| 2.000 | 4.000000 |
| 3.000Your value | 9.000000 |
| 4.000 | 16.000000 |
| 5.000 | 25.000000 |
| 6.000 | 36.000000 |
9.000000J
Open with these values4.000000J
Open with these values0.050000J
Open with these valuesE = ½ × L × I²
| L (H), I (A) | What it is | Energy (J) |
|---|---|---|
| 0.001, 10 | 1 mH choke at 10 A | 0.05 |
| 1, 1 | 1 H coil at 1 A | 0.5 |
| 10, 0.5 | 10 H coil at 0.5 A | 1.25 |
| 0.5, 4 | 0.5 H coil at 4 A | 4 |
| 2, 3 | 2 H coil at 3 A | 9 |
| 2, -3 | same coil, current reversed | 9 |
Multiply half the inductance by the current squared: E = ½ × L × I². Use henries and amperes and the answer comes out in joules. A 2 H coil carrying 3 A stores 9 J.
In the magnetic field the current creates around the coil. As long as current keeps flowing, the field and its energy persist. The inductor pushes that energy back into the circuit when the current tries to fall.
Because the current is squared in the formula. Doubling it multiplies the energy by four and tripling it by nine. The inductance enters only to the first power, so it scales the energy in direct proportion.
No. The current is squared, so a reversed current stores exactly the same energy as its positive counterpart. A 2 H coil stores 9 J at 3 A and 9 J at minus 3 A.
Henries for inductance and amperes for current, which gives joules. A coil rated in millihenries has to be divided by 1000 first, so 5 mH becomes 0.005 H. One joule equals one watt-second.
Information, not professional advice.
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