- Moles of solute (mol)
- 0.5mol
- Volume of solution (L)
- 2L
0.2500mol/L
Open with these values0.2500mol/L
Result: 0.2500 mol/LMolarity is moles of solute divided by litres of solution: 0.5 mol in 2 L gives 0.25 mol/L, also written 0.25 M. Use the volume of the finished solution, not the solvent you started with. Litres, never millilitres — 250 mL is 0.25 L, and mixing the two is a factor of a thousand.
0.2500mol/L
Open with these values1.0000mol/L
Open with these values0.4000mol/L
Open with these valuesMolarity = moles ÷ litres of solution
Molarity is defined per litre of the finished solution. Dissolve the solute and then top up to the wanted volume in a volumetric flask — that is the standard lab method.
The volume field is in litres, so 250 mL goes in as 0.25 L. With 0.1 mol that gives 0.4 mol/L; mixing the two units is a factor of a thousand.
A 1 M solution holds one mole of solute per litre of solution. Below 1 M is dilute, above it concentrated; household vinegar is roughly 0.8 M acetic acid.
It depends on the volume of the solution, and liquids expand when heated. The same amount of solute over a larger volume gives a marginally lower molarity.
I dissolved 0.5 mol in 2 L of water, so the solution is 0.25 mol/L.
Only if the finished solution measures 2 L. Molarity counts litres of solution, not litres of solvent you started with.
0.1 mol in 250 mL is 0.1 ÷ 250.
The field takes litres: 250 mL is 0.25 L, so it is 0.1 ÷ 0.25 = 0.4 mol/L.
Zero moles is not a valid entry.
It is allowed and returns 0 mol/L, pure solvent. Only the volume has to stay above zero.
| Moles (mol), volume (L) | Description | Molarity (mol/L) |
|---|---|---|
| 0, 1 | Pure solvent | 0 |
| 0.1, 0.25 | Small flask | 0.4 |
| 0.5, 2 | Dilute solution | 0.25 |
| 1, 1 | One molar | 1 |
| 2, 0.5 | Concentrated solution | 4 |
Divide the moles of solute by the volume of solution in litres: molarity = moles ÷ volume. For 0.5 mol of solute dissolved in 2 L of solution, that is 0.5 ÷ 2 = 0.25 mol/L. Keep the amount in moles and the volume in litres to get the result in mol/L.
Solute amount in moles (mol), solution volume in litres (L), and molarity in moles per litre (mol/L). The unit mol/L is also written M and read as molar, so 0.25 mol/L is the same as 0.25 M.
Always the total volume of the finished solution, not the volume of solvent you started with. Molarity is defined per litre of solution, so dissolving solute and then topping up to a known volume in a volumetric flask is the standard lab method.
A 1 M solution contains one mole of solute per litre of solution. Concentrations below 1 M are dilute and those above 1 M are concentrated. For comparison, household vinegar is roughly 0.8 M acetic acid.
Slightly, yes. Molarity depends on the volume of the solution, and liquids expand when heated, so the same amount of solute spread over a larger volume gives a marginally lower molarity. For precise work, prepare and use solutions at a stated temperature.
Information, not professional advice.
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