- Base edge b (square base)
- 6
- Slant height l (up a face, not vertical)
- 5
96.00
Open with these values96.00units²
Result: 96.00 units²A square pyramid is one square base plus four identical triangles: A = b² + 2 × b × l. With a base edge of 6 and a slant height of 5 that is 36 + 60 = 96 square units. The slant height runs up the middle of a face — it is not the vertical height of the pyramid.
Held fixed: Base edge b (square base) 6.000.
| Slant height l (up a face, not vertical) | Result |
|---|---|
| 2.000 | 60.00 |
| 4.000 | 84.00 |
| 5.000Your value | 96.00 |
| 6.000 | 108.00 |
| 8.000 | 132.00 |
| 10.000 | 156.00 |
96.00
Open with these values3.00
Open with these values260.00
Open with these valuesA = b² + 2 × b × l
| Base edge, slant height | Lateral surface | Base + lateral | Total surface |
|---|---|---|---|
| 0.5, 2 | 2 | 0.25 + 2 | 2.25 |
| 1, 1 | 2 | 1 + 2 | 3 |
| 2, 3 | 12 | 4 + 12 | 16 |
| 4, 4.5 | 36 | 16 + 36 | 52 |
| 6, 5 | 60 | 36 + 60 | 96 |
| 10, 8 | 160 | 100 + 160 | 260 |
For a square pyramid, add the base area to the four triangular faces: A = b² + 2 × b × l, with b the base edge and l the slant height. With b = 6 and l = 5 that is 36 + 60 = 96 square units.
It is the distance from the middle of a base edge straight up the centre of a triangular face to the apex, the face apothem. It is not the vertical height of the pyramid. Surface area uses it because each face is a triangle whose height is that slant.
The lateral surface is only the four triangles, 2 × b × l — the part you would paint or clad. The total adds the square base b² on top. Use the lateral figure when the base sits on the ground and is never seen.
For a right square pyramid the slant height is √(h² + (b ÷ 2)²), where h is the vertical height and b the base edge. Work that out first, then enter it here.
Whatever you entered, squared. Base edge and slant height in centimetres give square centimetres, in inches square inches. Both inputs must use the same unit.
Information, not professional advice.
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