- Number of sides
- 6
- Length of one side
- 4
41.569219
Open with these values41.569219units²
Result: 41.569219 units²Works for any regular shape from a triangle upward: n × s² ÷ (4 tan(π ÷ n)). All sides must be equal — for an irregular shape, split it into triangles instead. More sides at the same side length always means more area.
41.569219
Open with these values0.433013
Open with these values43.455844
Open with these valuesA = n × s² ÷ (4 × tan(π ÷ n))
| Sides, side length | Shape | Area |
|---|---|---|
| 3, 1 | triangle | 0.433013 |
| 5, 2 | pentagon | 6.881910 |
| 4, 5 | square | 25.000000 |
| 6, 4 | hexagon | 41.569219 |
| 8, 3 | octagon | 43.455844 |
Square the side, multiply by the number of sides, then divide by four times the tangent of π ÷ n. A hexagon with side 4 covers about 41.57 square units.
No. It assumes every side and every angle is the same. An irregular polygon has to be split into triangles and added up.
It does mathematically — tan(45°) is exactly 1. In floating point it lands on 25.000000000000004, and the calculator reports the value it actually computes rather than tidying it.
The shape approaches a circle. At a hundred sides it is already within a hundredth of a per cent of the circle with the same perimeter.
Information, not professional advice.
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