- First diagonal
- 6
- Second diagonal
- 8
24.00
Open with these values24.00units²
Result: 24.00 units²Half the product of the diagonals: d₁ × d₂ ÷ 2. Diagonals of 6 and 8 give 24. The halving is easy to forget — a square with both diagonals 10 has an area of 50, not 100, because its side is 7.07 and not 10.
Held fixed: First diagonal 6.000.
| Second diagonal | Result |
|---|---|
| 2.000 | 6.00 |
| 4.000 | 12.00 |
| 6.000 | 18.00 |
| 8.000Your value | 24.00 |
| 10.000 | 30.00 |
| 12.000 | 36.00 |
| 14.000 | 42.00 |
| 16.000 | 48.00 |
24.00
Open with these values30.00
Open with these values50.00
Open with these valuesA = d₁ × d₂ ÷ 2
| Diagonals | Side | Area |
|---|---|---|
| 2, 2 | 1.414 | 2 |
| 4, 6 | 3.606 | 12 |
| 6, 8 | 5 | 24 |
| 12, 5 | 6.5 | 30 |
| 10, 10 | 7.071 | 50 |
Multiply the two diagonals and halve the result. Diagonals of 6 and 8 give 24 square units.
Then it works like any parallelogram: base times perpendicular height. The diagonal formula is only easier when the diagonals are what you can measure.
The diagonals cross at right angles and bisect each other, so the side is √((d₁÷2)² + (d₂÷2)²). For 6 and 8 that is exactly 5.
Yes, the one with equal diagonals. Both diagonals of 10 give an area of 50 and a side of 7.07.
Information, not professional advice.
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