- Capacitance
- 0.001F
- Voltage
- 12V
0.012000C
Open with these values0.012000C
Result: 0.012000 CCharge is capacitance times voltage: a 1000 µF capacitor at 12 V holds 0.012 C. Double the voltage and it holds twice the charge — but four times the energy, because energy goes with the square.
Held fixed: Capacitance 0.001000000 F.
| Voltage (V) | Result (C) |
|---|---|
| 0.00 | 0.000000 |
| 5.00 | 0.005000 |
| 10.00 | 0.010000 |
| 12.00Your value | 0.012000 |
| 15.00 | 0.015000 |
| 20.00 | 0.020000 |
0.012000C
Open with these values0.001000C
Open with these values0.000005C
Open with these valuesQ = C × V
| Capacitance, voltage | What that is | Charge |
|---|---|---|
| 0.000001, 5 | 1 µF on a 5 V rail | 0.000005 |
| 0.0001, 10 | 100 µF at 10 V | 0.001 |
| 0.01, 1 | A 10 mF supercap at 1 V | 0.01 |
| 0.001, 12 | 1000 µF on a 12 V supply | 0.012 |
Its capacitance in farads times the voltage across it, giving coulombs. A 1000 µF capacitor at 12 V holds 0.012 C.
Energy is half the capacitance times the voltage squared, so the same part holds 0.072 J. Note that doubling the voltage doubles the charge but quadruples the energy.
The charge is exactly zero. A capacitor with no voltage across it stores nothing, however large its capacitance.
No. The rating is a limit on the dielectric, not a suggestion, and an electrolytic that is pushed past it can vent or fail short. Stay well below it, especially where ripple or transients are present.
Information, not professional advice.
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