- Load force (output)
- 500N
- Effort force (input)
- 100N
5.000
Open with these values5.000
Result: 5.000Divide the load force by the effort force. Above 1 the machine multiplies your push — a crowbar, a block and tackle, a ramp. Exactly 1 only changes direction. Below 1 you trade force for distance or speed, like a bicycle gear. Use the same force unit on both sides; the answer is a plain ratio.
5.000
Open with these values4.000
Open with these values0.250
Open with these valuesMA = load force ÷ effort force
| Load, effort | What it means | MA |
|---|---|---|
| 50, 200 | trades force for distance | 0.25 |
| 300, 300 | direction only | 1 |
| 1000, 250 | quadruples your push | 4 |
| 500, 100 | five times your push | 5 |
| 900, 150 | six times your push | 6 |
Divide the load force by the effort force. A load of 500 N lifted with 100 N of effort gives 5. Use the same force unit for both so the ratio comes out unitless.
It is how many times the machine multiplies your input force. Above 1 it multiplies force, exactly 1 only changes its direction, below 1 it trades force for speed or distance.
No. One force divided by another cancels the units, so the result is a plain ratio. That is why the answer reads 5 rather than 5 N.
The actual one, taken from the forces you enter. In a frictionless machine it would equal the ideal value set by lengths or radii; friction usually puts the real figure a little below that.
Anywhere a simple machine multiplies force: a crowbar prying a lid, a block and tackle lifting an engine, a ramp rolling a barrel up, gears in a bike or a winch.
Information, not professional advice.
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