No ads, no sign-upChecked 2026-08-24

Parallel-Plate Capacitor Calculator

Result

88.5419pF

Result: 88.5419 pF

Capacitance grows with plate area and shrinks with the gap: C = ε₀ × εr × A ÷ d. Two plates of 0.01 m² one millimetre apart in air hold 88.54 pF. Halving the gap doubles the capacitance, which is why real capacitors use very thin dielectric films.

The numbers at a glance

Held fixed: Plate area A (m²) 0.010000 m², Plate separation d (mm) 1.000 mm.

Relative permittivity εrResult (pF)
1.00Your value88.5419
1.20106.2503
1.40123.9586
1.60141.6670
1.80159.3754
2.00177.0838

Worked examples

Case 1
Plate area A (m²)
0.01
Plate separation d (mm)
1mm
Relative permittivity εr
1

88.5419pF

Open with these values
Case 2
Plate area A (m²)
0.05
Plate separation d (mm)
2mm
Relative permittivity εr
4.5

996.0961pF

Open with these values
Case 3
Plate area A (m²)
0.005
Plate separation d (mm)
0.1mm
Relative permittivity εr
3

1,328.1282pF

Open with these values

How it's calculated

C = ε₀ × εr × A ÷ d

  1. StepEnter the overlapping area of one plate in square metres.
  2. StepEnter the gap between the plates in millimetres, usually the dielectric thickness.
  3. StepEnter the relative permittivity: 1 for air, higher for any insulator.
  4. ResultRead the capacitance in picofarads; divide by 1000 for nanofarads.

Reference table

A (m²), d (mm), εrIn nFCapacitance in pF
0.005, 0.1, 31.3281 nF1328.1282
0.01, 1, 10.0885 nF88.5419
0.02, 0.5, 2.20.7792 nF779.1685
0.05, 2, 4.50.9961 nF996.0961
0.1, 5, 10.1771 nF177.0838

Questions

How do I calculate the capacitance of a parallel-plate capacitor?

Multiply the electric constant ε₀, about 8.854 × 10⁻¹² F/m, by the relative permittivity and the plate area, then divide by the gap in metres. For 0.01 m², a gap of 1 mm and air between the plates that gives 88.541878 pF.

What is relative permittivity?

Also called the dielectric constant, it says how much better a material stores electric field energy than a vacuum, and it has no unit. Vacuum and air are about 1, paper around 3, glass and mica roughly 5 to 10, and many ceramics reach the hundreds. A higher value multiplies the capacitance by the same factor.

Why does a smaller gap increase capacitance?

Capacitance is inversely proportional to the plate separation, so halving the gap doubles it. A smaller gap lets the same voltage create a stronger field, which pulls more charge onto the plates.

What is the difference between picofarads and nanofarads?

They are two scales for the same quantity: 1 nF is 1000 pF, and one farad is 10¹² pF. Small air-gap capacitors are usually quoted in pF, larger film types in nF.

Which units do I enter?

Plate area in square metres, separation in millimetres, and the relative permittivity as a plain number. The calculator converts the gap to metres itself and returns picofarads.

Sources and last check

  1. en.wikipedia.org

Information, not professional advice.