Drop · share · load voltage: 3.36 V · 2.8 % · 116.64 V at load
In other units
65.617 ft
Examples
Drop · share · load voltage3.36 V · 2.8 % · 116.64 V at load
Enter current, one-way length and supply voltage. Choose DC, single-phase or balanced three-phase and a conductor. Read drop in V and %, plus voltage at the load. AC presets use Schneider's XLPE table for lighting (cos φ=1) or motors (0.8); manual AC is a resistance-only estimate, not a wiring approval.
The numbers at a glance
Held fixed: Circuit DC, Current (A) 10.000 A, One-way run length 20.000 m, Supply voltage (V) 120.00 V, Conductor / cross-section Manual ρ / cross-section, AC load model (ignored for DC) Lighting, cos φ = 1, Resistivity (manual only) 0.000000016800 Ω·m.
DC: ΔV = 2ILρ/A; AC presets: ΔV = KIL (L in km, K from cable table)
1StepChoose DC, single-phase or balanced three-phase and enter current, supply voltage and one-way cable length.Current (A)=10A·Supply voltage (V)=120V·One-way run length=20m
2StepSelect a copper/aluminium size; for manual input, enter resistivity and cross-section in m².Resistivity (manual only)=0.0000000168Ω·m
3StepFor AC presets, choose the lighting or normal motor load table; the cable assumptions come from the cited source.AC load model (ignored for DC)=Lighting, cos φ = 1
4ResultRead volts lost, percentage of supply and load-end voltage for this run only; upstream drop is excluded.Supply voltage (V)=120V·AC load model (ignored for DC)=Lighting, cos φ = 1→3.36 V · 2.8 % · 116.64 V at load
Reference table
Mode, current, one-way length, conductor
What that run is
Voltage drop (V)
5, 10, 0.0000000168, 0.0000015
5 A over 10 m of 1.5 mm² copper
1.12
30, 25, 0.0000000168, 0.00001
30 A over 25 m of 10 mm² copper
2.52
10, 20, 0.0000000168, 0.000002
10 A over 20 m of 2 mm² copper
3.36
15, 30, 0.0000000168, 0.000004
15 A over 30 m of 4 mm² copper
3.78
20, 50, 0.0000000282, 0.000006
20 A over 50 m of 6 mm² aluminium
9.40
Single-phase, 20 A, 20 m, Cu 2.5 mm²
Schneider lighting table, K = 19 V/A/km
7.60
Three-phase, 100 A, 50 m, Cu 35 mm²
Schneider motor table, K = 1 V/A/km
5.00
Questions
How do I calculate voltage drop?
For manual DC, use 2 × one-way length × current × resistivity / area. The selected AC cable tables already include the circuit and load factors; multiply their K by amperes and one-way kilometres.
Why do I enter the one-way length?
DC and single-phase circuits include the return path; balanced three-phase uses a different phase factor. Enter the distance from supply to load once: the formula or sourced cable coefficient handles the circuit path.
What do the AC cable presets assume?
The cited Schneider table models copper or aluminium XLPE cable, with lighting at cos φ = 1 or motor normal service at cos φ = 0.8. Its rounded K values include resistance, reactance and circuit geometry; manual AC input omits reactance and is only a resistance-based approximation.
Does a low percentage mean the cable is safe?
No. This result estimates voltage loss on the entered run only; it excludes upstream loss, ampacity, overcurrent protection, installation method and local code requirements. Have a qualified professional assess an actual installation.
What units can I enter?
The one-way distance accepts metres or feet; the calculator converts feet internally. Cable presets are named by mm², while the legacy manual cross-section is entered in m² (1 mm² = 0.000001 m²). Supply and load voltages use the same V basis.
Can I estimate DC wire heating from this result?
For the simple DC run, current times voltage drop estimates heat lost in the pair of conductors. The three-phase AC loss is not generally obtained by multiplying its displayed line-to-line drop by current.