Case 1
- Mass of the sample
- 18g
- Molar mass
- 18.015g/mol
0.999167mol
Open with these valuesChange any value to update the result.
0.999167mol
Amount of substance: 0.999167 molYour current valid inputs, with one value varied across the range.
Held fixed: Mass of the sample 18.0000 g.
| Molar mass (g/mol) | Amount of substance (mol) |
|---|---|
| 15.0000 | 1.200000 |
| 17.5000 | 1.028571 |
| 18.0150Your value | 0.999167 |
| 20.0000 | 0.900000 |
| 22.5000 | 0.800000 |
Divide the mass by the molar mass: n = m ÷ M, grams over grams per mole leaves moles. 18 g of water at 18.015 g/mol is 0.999167 mol — almost exactly one mole, which is where the round number 18 for water comes from. Convert kilograms or milligrams to grams first.
0.999167mol
Open with these values1.000000mol
Open with these values5.550930mol
Open with these valuesn = m ÷ M
The grams only cancel if the mass is in grams and the molar mass in g/mol. Kilograms or milligrams give a result off by a factor of 1000 with nothing looking wrong.
There is no substance list here; the second field takes the molar mass added up from the formula. Water is 2 × 1.008 + 15.999 ≈ 18.015 g/mol, table salt about 58.44 g/mol.
18 g of water at 18.015 g/mol is 0.999167 mol, almost exactly one mole. At the rounded 18 g/mol, 9 g is exactly half a mole.
Multiply the result by the Avogadro constant, 6.02214076 × 10²³ per mole. So 0.5 mol holds about 3.011 × 10²³ molecules.
Misconceptionn = m × M — mass times molar mass.
CorrectionIt is a division, n = m ÷ M. 9 g at 18 g/mol is 0.5 mol, where multiplying would give 162.
MisconceptionMy sample is 0.1 kg, so I enter 0.1.
CorrectionConvert to grams first: 0.1 kg is 100 g, which at 18.015 g/mol gives 5.550930 mol.
Misconception18 g of water is exactly one mole.
CorrectionIt is 0.999167 mol. One mole of water weighs 18.015 g; the round 18 is a convenience.
| Mass (g), molar mass (g/mol) | Substance | Amount (mol) |
|---|---|---|
| 9, 18 | Water, rounded molar mass | 0.500000 |
| 18, 18.015 | Water | 0.999167 |
| 44, 44.01 | Carbon dioxide | 0.999773 |
| 58.44, 58.44 | Sodium chloride | 1.000000 |
| 100, 18.015 | Water | 5.550930 |
Divide the mass of your sample by the molar mass of the substance: n = m ÷ M. Use grams for the mass and grams per mole for the molar mass. For example, 18 g of water at 18.015 g/mol is 0.999167 mol.
A mole is the SI unit for the amount of substance, and one mole contains exactly 6.02214076 × 10²³ entities — atoms, molecules or formula units. That figure is the Avogadro constant, fixed by definition since 2019.
Molar mass is the mass of one mole in grams per mole. Add up the standard atomic weights of every atom in the formula: water is 2 × 1.008 + 15.999 ≈ 18.015 g/mol, table salt about 58.44 g/mol.
Multiply the amount of substance by the Avogadro constant: molecules = n × 6.022 × 10²³. So 0.5 mol holds about 3.011 × 10²³ molecules.
Grams for the mass and grams per mole for the molar mass, which leaves the amount in moles because the grams cancel. A mass in kilograms or milligrams has to be converted to grams first, or the result is off by a factor of 1000.
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