Case 1
- Radius
- 5
523.598776
Open with these valuesChange any value to update the result.
523.598776units³
Sphere volume: 523.598776 units³Your current valid inputs, with one value varied across the range.
| Radius | Sphere volume |
|---|---|
| 4.000 | 268.082573 |
| 5.000Your value | 523.598776 |
| 6.000 | 904.778684 |
Four thirds of π times the radius cubed. The radius enters as a cube, so doubling it multiplies the volume by eight: a ball of radius 5 holds 523.6 units³, one of radius 10 holds 4188.8. If you measured across the ball, halve that first.
523.598776
Open with these values4.188790
Open with these values4,188.790205
Open with these valuesV = ⁴⁄₃ × π × r³
The radius enters as a cube, so the volume grows with 2³ = 8. Radius 5 holds 523.6 units³ and radius 10 holds 4188.8 — eight times as much from twice the measurement.
Enter the radius in one single length unit; the volume comes back in the cube of that unit. The formula fixes no unit of its own.
Radius 5 is 500π ÷ 3, radius 2 is 32π ÷ 3. The decimal beside it is only that same number written out, so any row can be checked by hand.
MisconceptionThe ball measures 10 across, so I enter 10.
CorrectionHalve it first: the radius is 5. Entering the diameter instead overstates the volume eightfold, 4188.8 in place of 523.6.
MisconceptionThe volume of a sphere is πr³.
CorrectionIt is four thirds of that. Radius 1 gives 4.188790, and dropping the four thirds understates every result by a quarter.
MisconceptionA half sphere needs a formula of its own.
CorrectionIt is exactly half of this figure, ⅔πr³. The separate hemisphere calculator additionally accounts for the flat circular face.
| Radius | Exact | Volume |
|---|---|---|
| 0.5 | π ÷ 6 | 0.523599 |
| 1 | 4π ÷ 3 | 4.188790 |
| 2 | 32π ÷ 3 | 33.510322 |
| 5 | 500π ÷ 3 | 523.598776 |
| 10 | 4000π ÷ 3 | 4188.790205 |
Cube the radius, multiply by π and then by four thirds. A radius of 5 gives 500π ÷ 3, about 523.6 cubic units.
Halve it. A ball 10 units across has a radius of 5, and entering 10 by mistake overstates the volume eightfold.
Because the radius is cubed. Doubling the radius multiplies the volume by 2³ = 8, which is why a slightly larger ball holds far more than it looks.
Exactly half of this, or ⅔πr³. There is a separate hemisphere calculator that also gives the flat circular face.
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